Design a serial 2's complementer with a shift register and a flip-flop. The binary number is shifted out from one end of the shift register, and it's 2's complement. When shift = 1, the content of the register is shifted by one position. 6-10) Design a serial 2's complementer with shift register and a flip-flop. The binary number.

I know this question has been asked and there already are answers to this question on the Internet. I just want to ask you where I am wrong in my way of thinking. Blank udostovereniya mvd skachatj phone number. When I first saw this question, the shortcut -keep copying until you see a 1 and then complement the rest- hadn't occurred to me. So I thought I would just complement the bit, add 1 to it and if I get a carry then I would keep it in the flip flop to add it to the next bit coming from the input. Meaning that, In State-0 if the input is 0 then I should output '0' (after complementing) and keep that carry '1' in the flip-flop so flip-flop goes from state-0 to state-1. If the input is 1 then I should output '1' but the flip-flop remains in the same state which is state-0. In State-1 if the input is 0 then I should output '1' -since 2's complement would be 10 and I have a carry '1' in the flip-flop- I would get another carry so the state remains the same.

If the input is 1 then I should output '0' and the flip-flop remains in the same state as well. Here is my state diagram: +---------+-------+-------+--------+ Present Next State Input State Output A x A y 0 0 1 0 0 1 0 1 1 0 1 1 1 1 1 0 +---------+-------+-------+--------+ After getting the equations from the table above. I get a circuit like so: – Schematic created using Can you please help me to figure out what's wrong with my way of thinking? Thank you in advance.:). I just figured out the problem and here I am explaining.

If you were trying to solve this problem the same way I was trying (without thinking about the shortcut like 'output the same value till you see a bit of value 1 and then complement others in the string.' ) then we will have 2 states.

State-1 (Initial State - Carry-1 State) Which we have a carry-1 to add to the least significant bit of the string after complementing. Because that's what you would normally do when you are trying to get the 2's complement of a bit string. You just complement the entire string and add 1 to the least significant bit.

You could name this state, State-0 as well but I am just naming it State-1 not to get confused. So that I know I have a carry 1 in the flip-flop. State-0 (Which signifies that you don't have any carry left) This state means that you have no carry left in hand. So you just complement the bit at the input. Let's inspect what possibilities we can get when trying to get the 2's complement of a bit string. • In the initial state you could get a 1 whose 1's complement is 0 and with a carry in hand equals to 1.

Since that sum doesn't generate a carry. You have no carry left in hand and you go to State-0. • Again in the initial state you could get a 0 whose 1's complement is 1 and with a carry in hand this sum equals to 10, which means you will again have a carry in hand and therefore remain in the same state which is State-1. But the output will be 0. • In State-0 you could get a 0 again and since you don't have any carry in hand you just output the 1's complement of 0 which is equal to 1. • Again in State-0 you could have 1 at the input and since you don't have any carry your output would be equal to 0. Having that said, we draw a state table as follows: +---------+-------+-------+--------+ Present Next State Input State Output A x A y 1 0 1 0 1 1 0 1 0 0 0 1 0 1 0 0 +---------+-------+-------+--------+ Looking at the table, we get a state diagram like so: Then we get this circuit: – Schematic created using.

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4- bit adder, 2's compliment subtractor circuit using a 4-bit adder IC. Verification of the operation of the circuit.

Apparatus: Logic trainer kit, 4-bit adder (IC 7483), X-OR gates (IC 7486), wires Theory: IC 7483 is a 4 bit adder. In binary, subtraction can be performed by using 2's complement method.

In this method negative number is converted into its 2's complement and it is added to the other number. The result of this addition is the subtraction of origin numbers.

If we modify the adder circuit, such that 2's complement and simple representation are presented, we can perform addition subtraction as required. X-OR gate is used as a controlled inverter/ buffer for this purpose. Use it as buffer for addition and inverter for subtraction. Procedure: 1. Connect the IC 7483 and IC 7486 as per diagram. Connect all A's and all B's to logic sources, S's to logic indicators. Connect Cin to logic 0, this will set the circuit for addition.

Give various input combinations, verify adder operation. Here Cout is MSB of addition. Connect Cin to logic 1, this will set the circuit for subtraction by 2's complement method. Give various input combinations and observe outputs.